Integrand size = 28, antiderivative size = 111 \[ \int \frac {(a+i a \tan (c+d x))^3}{(e \sec (c+d x))^{3/2}} \, dx=-\frac {10 i a^3 \sqrt {e \sec (c+d x)}}{3 d e^2}-\frac {10 a^3 \sqrt {\cos (c+d x)} \operatorname {EllipticF}\left (\frac {1}{2} (c+d x),2\right ) \sqrt {e \sec (c+d x)}}{3 d e^2}-\frac {4 i a (a+i a \tan (c+d x))^2}{3 d (e \sec (c+d x))^{3/2}} \]
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Time = 0.12 (sec) , antiderivative size = 111, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.143, Rules used = {3577, 3567, 3856, 2720} \[ \int \frac {(a+i a \tan (c+d x))^3}{(e \sec (c+d x))^{3/2}} \, dx=-\frac {10 i a^3 \sqrt {e \sec (c+d x)}}{3 d e^2}-\frac {10 a^3 \sqrt {\cos (c+d x)} \operatorname {EllipticF}\left (\frac {1}{2} (c+d x),2\right ) \sqrt {e \sec (c+d x)}}{3 d e^2}-\frac {4 i a (a+i a \tan (c+d x))^2}{3 d (e \sec (c+d x))^{3/2}} \]
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Rule 2720
Rule 3567
Rule 3577
Rule 3856
Rubi steps \begin{align*} \text {integral}& = -\frac {4 i a (a+i a \tan (c+d x))^2}{3 d (e \sec (c+d x))^{3/2}}-\frac {\left (5 a^2\right ) \int \sqrt {e \sec (c+d x)} (a+i a \tan (c+d x)) \, dx}{3 e^2} \\ & = -\frac {10 i a^3 \sqrt {e \sec (c+d x)}}{3 d e^2}-\frac {4 i a (a+i a \tan (c+d x))^2}{3 d (e \sec (c+d x))^{3/2}}-\frac {\left (5 a^3\right ) \int \sqrt {e \sec (c+d x)} \, dx}{3 e^2} \\ & = -\frac {10 i a^3 \sqrt {e \sec (c+d x)}}{3 d e^2}-\frac {4 i a (a+i a \tan (c+d x))^2}{3 d (e \sec (c+d x))^{3/2}}-\frac {\left (5 a^3 \sqrt {\cos (c+d x)} \sqrt {e \sec (c+d x)}\right ) \int \frac {1}{\sqrt {\cos (c+d x)}} \, dx}{3 e^2} \\ & = -\frac {10 i a^3 \sqrt {e \sec (c+d x)}}{3 d e^2}-\frac {10 a^3 \sqrt {\cos (c+d x)} \operatorname {EllipticF}\left (\frac {1}{2} (c+d x),2\right ) \sqrt {e \sec (c+d x)}}{3 d e^2}-\frac {4 i a (a+i a \tan (c+d x))^2}{3 d (e \sec (c+d x))^{3/2}} \\ \end{align*}
Time = 1.97 (sec) , antiderivative size = 123, normalized size of antiderivative = 1.11 \[ \int \frac {(a+i a \tan (c+d x))^3}{(e \sec (c+d x))^{3/2}} \, dx=-\frac {2 a^3 \sec ^2(c+d x) \left (7 i \cos (c+d x)+5 \sqrt {\cos (c+d x)} \operatorname {EllipticF}\left (\frac {1}{2} (c+d x),2\right ) (\cos (c+d x)-i \sin (c+d x))+3 \sin (c+d x)\right ) (\cos (c+4 d x)+i \sin (c+4 d x))}{3 d (e \sec (c+d x))^{3/2} (\cos (d x)+i \sin (d x))^3} \]
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Time = 12.28 (sec) , antiderivative size = 165, normalized size of antiderivative = 1.49
method | result | size |
default | \(-\frac {2 a^{3} \left (5 i F\left (i \left (-\csc \left (d x +c \right )+\cot \left (d x +c \right )\right ), i\right ) \sqrt {\frac {1}{\cos \left (d x +c \right )+1}}\, \sqrt {\frac {\cos \left (d x +c \right )}{\cos \left (d x +c \right )+1}}+5 i \sec \left (d x +c \right ) F\left (i \left (-\csc \left (d x +c \right )+\cot \left (d x +c \right )\right ), i\right ) \sqrt {\frac {1}{\cos \left (d x +c \right )+1}}\, \sqrt {\frac {\cos \left (d x +c \right )}{\cos \left (d x +c \right )+1}}+4 i \cos \left (d x +c \right )-4 \sin \left (d x +c \right )+3 i \sec \left (d x +c \right )\right )}{3 e d \sqrt {e \sec \left (d x +c \right )}}\) | \(165\) |
parts | \(\text {Expression too large to display}\) | \(1146\) |
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Result contains higher order function than in optimal. Order 9 vs. order 4.
Time = 0.07 (sec) , antiderivative size = 82, normalized size of antiderivative = 0.74 \[ \int \frac {(a+i a \tan (c+d x))^3}{(e \sec (c+d x))^{3/2}} \, dx=-\frac {2 \, {\left (-5 i \, \sqrt {2} a^{3} \sqrt {e} {\rm weierstrassPInverse}\left (-4, 0, e^{\left (i \, d x + i \, c\right )}\right ) + \sqrt {2} {\left (2 i \, a^{3} e^{\left (2 i \, d x + 2 i \, c\right )} + 5 i \, a^{3}\right )} \sqrt {\frac {e}{e^{\left (2 i \, d x + 2 i \, c\right )} + 1}} e^{\left (\frac {1}{2} i \, d x + \frac {1}{2} i \, c\right )}\right )}}{3 \, d e^{2}} \]
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\[ \int \frac {(a+i a \tan (c+d x))^3}{(e \sec (c+d x))^{3/2}} \, dx=- i a^{3} \left (\int \frac {i}{\left (e \sec {\left (c + d x \right )}\right )^{\frac {3}{2}}}\, dx + \int \left (- \frac {3 \tan {\left (c + d x \right )}}{\left (e \sec {\left (c + d x \right )}\right )^{\frac {3}{2}}}\right )\, dx + \int \frac {\tan ^{3}{\left (c + d x \right )}}{\left (e \sec {\left (c + d x \right )}\right )^{\frac {3}{2}}}\, dx + \int \left (- \frac {3 i \tan ^{2}{\left (c + d x \right )}}{\left (e \sec {\left (c + d x \right )}\right )^{\frac {3}{2}}}\right )\, dx\right ) \]
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\[ \int \frac {(a+i a \tan (c+d x))^3}{(e \sec (c+d x))^{3/2}} \, dx=\int { \frac {{\left (i \, a \tan \left (d x + c\right ) + a\right )}^{3}}{\left (e \sec \left (d x + c\right )\right )^{\frac {3}{2}}} \,d x } \]
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\[ \int \frac {(a+i a \tan (c+d x))^3}{(e \sec (c+d x))^{3/2}} \, dx=\int { \frac {{\left (i \, a \tan \left (d x + c\right ) + a\right )}^{3}}{\left (e \sec \left (d x + c\right )\right )^{\frac {3}{2}}} \,d x } \]
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Timed out. \[ \int \frac {(a+i a \tan (c+d x))^3}{(e \sec (c+d x))^{3/2}} \, dx=\int \frac {{\left (a+a\,\mathrm {tan}\left (c+d\,x\right )\,1{}\mathrm {i}\right )}^3}{{\left (\frac {e}{\cos \left (c+d\,x\right )}\right )}^{3/2}} \,d x \]
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